Hi everybody,
>>> c=[(5,3), (6,8)]
>From c, I want to obtain a list with 5,3,6, and 8, in any order.
I do this:
>>> [i for (i,j) in c] + [ j for (i,j) in c]
[5, 6, 3, 8]
Is there a quicker way to do this?
Thanks
Julien
--
python -c "print ''.join([chr(154 - ord(c)) for c in '*9(9&(18%.9&1+,\'Z
(55l4('])"
"When a distinguished but elderly scientist states that something is
possible, he is almost certainly right. When he states that something is
impossible, he is very probably wrong." (first law of AC Clarke)
--
http://mail.python.org/mailman/listinfo/python-list
