Aaron Scott wrote: > I've been trying to read up on this, but I'm not sure what the > simplest way to do it is. > > I have a list of string. I'd like to check to see if any of the > strings in that list matches another string. > > Pseudocode: > > if "two" in ["one", "two", "three", "four"]: > return True
Why /pseudo/ ? >>> if "two" in ["one", "two", "three", "four"]: ... print "match" ... else: ... print "no match" ... match >>> if "seven" in ["one", "two", "three", "four"]: ... print "match" ... else: ... print "no match" ... no match > Is there any built-in iteration that would do such a thing, or do I > have to write a function to check for me? I was using .index on the > list, but it would return True for strings that contained the search > string rather than match it exactly, leading to false positives in my > code. You didn't check carefully. list.index() gives you a value error when no matching item is found: >>> ["one", "two", "three", "four"].index("seven") Traceback (most recent call last): File "<stdin>", line 1, in <module> ValueError: list.index(x): x not in list Peter -- http://mail.python.org/mailman/listinfo/python-list