lookon <[EMAIL PROTECTED]> writes: > I have a url of image, and I want to get the filename and extension of > the image. How to write in python? > > for example, the url is http://a.b.com/aaa.jpg?version=1.1 > > how can I get aaa and jpg by python?
Without res: >>> url=" http://a.b.com/aaa.jpg?version=1.1"; >>> url.rsplit('/', 1)[1].split('?')[0].split('.') ['aaa', 'jpg'] -- Arnaud -- http://mail.python.org/mailman/listinfo/python-list
![http://a.b.com/aaa.jpg?version=1.1"](http://a.b.com/aaa.jpg?version=1.1"){kind=link}