On Thu, Nov 27, 2008 at 2:39 PM, TP <[EMAIL PROTECTED]> wrote:
> [EMAIL PROTECTED] wrote:
>
>>> >>> a=("1","2")
>>> >>> b=[("3","4"),("5","6")]
>>> >>> list(a)+b
>>> ['1', '2', ('3', '4'), ('5', '6')]
>>
>>>>> a = ("1", "2")
>>>>> b = [("3", "4"), ("5", "6")]
>>>>> [a] + b
>> [('1', '2'), ('3', '4'), ('5', '6')]
>
> Thanks a lot.
> Why this difference of behavior between list(a) and [a]?
Because list() is used to convert other iterable types into lists
(e.g. list("abc") ==> ['a','b','c'], list((c,d)) ==> [c,d],
list(set(x,y,z)) ==> [y, z, x]).
In contrast, a list literal just constructs a list. This makes sense
because the behavior of list() is useful and you can just use the
literal syntax instead for cases such as yours.
In Python 3.0, I believe you'll be able to use the splat operator to
do e.g. [a, *b] to get your desired result.
For reference:
list(a) <==> [x for x in a]
[a,b,c] <==> list((a,b,c))
Cheers,
Chris
--
Follow the path of the Iguana...
http://rebertia.com
>
> Julien
>
> --
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> (55l4('])"
>
> "When a distinguished but elderly scientist states that something is
> possible, he is almost certainly right. When he states that something is
> impossible, he is very probably wrong." (first law of AC Clarke)
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