Hi, I want to use a regex to match a string "poo" but not "poo\n" or "poo"+chr(13) or "poo"+chr(10) or "poo"+chr(10)+chr(13)
According to http://docs.python.org/library/re.html '.' (Dot.) In the default mode, this matches any character except a newline. If the DOTALL flag has been specified, this matches any character including a newline. So I tried a = re.compile(r'^.{1,50}$') print a.match("poo\n") <_sre.SRE_Match object at 0xb7767988> :-( The library says... '$' Matches the end of the string or just before the newline at the end of the string, and in MULTILINE mode also matches before a newline. foo matches both ‘foo’ and ‘foobar’, while the regular expression foo$ matches only ‘foo’. More interestingly, searching for foo.$ in 'foo1\nfoo2\n' matches ‘foo2’ normally, but ‘foo1’ in MULTILINE mode; searching for a single $ in 'foo\n' will find two (empty) matches: one just before the newline, and one at the end of the string. So that explains it but what am I to do then? I assume it isn't matching the newline itself as the returned string does not contain one but is there a switch that can stop $ matching 'just before the newline at the end of the string' or is there another character class I could use here? Any ideas greatly appreciated! Thanks, Roger. -- http://mail.python.org/mailman/listinfo/python-list
