Alphones wrote:
> Hi all,
>
>
> def getFunc(x):
> return lambda y : x + y
>
> if __name__ == '__main__':
> todo = []
> proc = getFunc(1)
> todo.append(lambda: proc(1))
> proc = getFunc(2)
> todo.append(lambda: proc(1))
> proc = getFunc(3)
> todo.append(lambda: proc(1))
>
> todo.append(lambda: getFunc(1)(1))
> todo.append(lambda: getFunc(2)(1))
> todo.append(lambda: getFunc(3)(1))
>
> for task in todo:
> print task()
>
> -----------
> the program outputs:
> 4
> 4
> 4
> 2
> 3
> 4
> in Python 2.6.
> is that excpected?
Yes. Creating a lambda will close over the current *names* in the scope,
*not* their respective values. For that, you need to create a new scope -
e.g. by bindig the value to a argument of the lambda:
lambdas = []
for i in xrange(10):
lambda i=i : i ** 2
for l in lambdas:
l()
Diez
--
http://mail.python.org/mailman/listinfo/python-list
