I apologize in advance for the newbie question. I'm trying to figure
out a way to find all of the occurrences of a regular expression in a
string including the overlapping ones.
For example, given the string 123456789
I'd like to use the RE ((2)|(4))[0-9]{3} to get the following matches:
2345
4567
Here's what I'm trying so far:
<code>
#!/usr/bin/env python
import re, repr, sys
string = "123456789"
pattern = '(((2)|(4))[0-9]{3})'
r1 = re.compile(pattern)
stringList = r1.findall(string)
for string in stringList:
print "string type is:", type(string)
print "string is:", string
</code>
Which produces:
<code>
string type is: <type 'tuple'>
string is: ('2345', '2', '2', '')
</code>
I understand that the findall method only returns the non-overlapping
matches. I just haven't figured out a function that gives me the
matches including the overlap. Can anyone point me in the right
direction? I'd also really like to understand why it returns a tuple
and what the '2', '2' refers to.
Thanks for your help!
-Ben
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