Hello,
I need to access the code inside of a context manager, i.e. the call to
with myManager(v=5) as x:
a=b
c=sin(x)
should cause the following output (minus the first line, if that's easier):
with myManager(v=5) as x: # I could live without this line
a=b
c=sin(x)
I can get the line number from the traceback (see below), and try to
find the block in the source, but that seems ugly to me.
class MyManager(object):
def __init__(self,name='name'):
# how to access the source code inside of the with block ?
f = traceback.extract_stack()
print f[0]
def __enter__(self):
pass
def __exit__(self,type,value,traceback):
if type is not None:
print 'exception'
pass
Any ideas?
Daniel
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