dpapathanasiou wrote:
> I have some old Common Lisp functions I'd like to rewrite in Python
> (I'm still new to Python), and one thing I miss is not having to
> declare local variables.
>
> For example, I have this Lisp function:
>
> (defun random-char ()
> "Generate a random char from one of [0-9][a-z][A-Z]"
> (if (< 50 (random 100))
> (code-char (+ (random 10) 48)) ; ascii 48 = 0
> (code-char (+ (random 26) (if (< 50 (random 100)) 65 97))))) ;
> ascii 65 = A, 97 = a
>
> My Python version looks like this:
>
> def random_char ():
> '''Generate a random char from one of [0-9][a-z][A-Z]'''
> if random.randrange(0, 100) > 50:
> return chr( random.randrange(0, 10) + 48 ) # ascii 48 = 0
> else:
> offset = 65 # ascii 65 = A
> if random.randrange(0, 100) > 50:
> offset = 97 # ascii 97 = a
> return chr( random.randrange(0, 26) + offset )
>
> Logically, it's equivalent of the Lisp version.
>
> But is there any way to avoid using the local variable (offset) in the
> Python version?
>
Yes, you can avoid using offset, but *why*. This certainly won't make
your code cleaner or more easily read/understood/maintainable.
return chr( random.randrange(0, 26) + (97 if random.randrange(0,
100) > 50 else 65)
or
if random.randrange(0, 100) > 50:
return chr( random.randrange(0, 26) + 97)
else:
return chr( random.randrange(0, 26) + 65)
or
return chr( random.randrange(0, 26) + [26,97][random.randrange(0,
100) > 50]
or
... probably other ways can be found ...
but what's wrong with you original code?
Gary Herron
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>
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