thanks guys.
cheers,
Stef
Terry Reedy wrote:
Stef Mientki wrote:
hello,
although this is not a real problem for me,
it was caused by a copying, instead of moving, a piece of code.
But I don't understand at all why the code below gives the error.
class derived_class, is defined twice,
the error is cuase by the second instance creation "test2="
for me even weirder, if I create test2 in another module, everything
works perfect ???
Any explanation would be welcome.
A different version of what Arnaud D. said:
==== start of code ===
class base_class ( object ) :
def __init__ ( self ) :
pass
class derived_class ( base_class ) :
def __init__ ( self ) :
base_class.__init__ ( self )
class final_class_1 ( derived_class ) :
In this line, 'derived_class' is evaluated when the class is defined
def __init__ ( self ) :
derived_class.__init__ ( self )
In this line, 'devired_class' is evaluated when the class is
instantiated and __init__ is called.
test1 = final_class_1 ()
Here, the object corresponding to 'derived_class in f_c_1.__init__is
the same as when f_c_1 was created.
class derived_class ( base_class ) :
def __init__ ( self ) :
base_class.__init__ ( self )
test2 = final_class_1 ()
Here, object corresponding to 'derived_class in f_c_1.__init__is no
longer the same as when f_c_1 was created.
==== end of code =====
==== error meassage =====
Traceback (most recent call last):
File "D:\Data_Python_25\PyLab_Works\module1.py", line 19, in <module>
test2 = final_class_1 ()
File "D:\Data_Python_25\PyLab_Works\module1.py", line 11, in __init__
derived_class.__init__ ( self )
TypeError: unbound method __init__() must be called with derived_class
This refers to the second 'derived_class', and f_c_1 ia *not* a
subclass of *that* class object.
instance as first argument (got final_class_1 instance instead)
tjr
--
http://mail.python.org/mailman/listinfo/python-list
--
http://mail.python.org/mailman/listinfo/python-list
