On 9 Nov., 05:04, Terry Reedy <[EMAIL PROTECTED]> wrote: > Have you written any Python code where you really wanted the old, > unpredictable behavior?
Sure: if len(L1) == len(L2): return sorted(L1) == sorted(L2) # check whether two lists contain the same elements else: return False It doesn't really matter here what the result of the sorts actually is as long as the algorithm leads to the same result for all permutations on L1 ( and L2 ). -- http://mail.python.org/mailman/listinfo/python-list