On Nov 4, 3:48 pm, Prateek <[EMAIL PROTECTED]> wrote:
> I've been using Python for a while (4 years) so I feel like a moron
> writing this post because I think I should know the answer to this
> question:
>
> How do I make a dictionary which has distinct key-value pairs for 0,
> False, 1 and True.
> As I have learnt, 0 and False both hash to the same value (same for 1
> and True).
>
> >>> b = {0:'xyz', False:'abc'}
> >>> b
>
> {0: 'abc'} # Am I the only one who thinks this is weird?
>
> This obviously stems from the fact that 0 == False but 0 is not False
> etc. etc.
>
> That doesn't help my case where I need to distinguish between the two
>
> The same issue applies in a list:
>
> Suppose I do:
>
> >>> a = [0, 1, True, False]
> >>> a.index(False)
>
> 0
>
> Wha??? Help.
Let me suggest using surrogate objects instead of True and False:
class TrueObject(object):
def __nonzero__(self):
return True
class FalseObject(object):
def __nonzero__(self):
return False
DistinctTrue = TrueObject()
DistinctFalse = FalseObject()
If that doesn't work and you really need the actual True and False
objects to be distinct, it's not too hard to special case a dict to
get it:
class special_dict(dict):
def __init__(self,*args,**kwargs):
self.true_surrogate = object()
self.false_surrogate = object()
super(special_dict,self).__init__(*args,**kwargs)
def __getitem__(self,value):
if value is True:
value = self.true_surrogate
elif value is False:
value = self.false_surrogate
super(special_dict,self).__getitem__(value)
## etc.
Carl Banks
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