atom = 'C1'
if '1' in atom:
print 'kk'
But, how can I do to identify in '1' all possibilities from 1-9, I
tried:
if '[1-9]', \d,...
You're reaching in the right direction (regexps), so just use
Python's "re" module:
import re
digit = re.compile(r'\d') # or "[0-9]"
for test in ["C1", "N98", "CJ", "3.141", "43+5i", ""]:
print test,
if digit.search(test):
print "has",
else:
print "doesn't have",
print "a digit in it"
The regexp can be tightened up if you want to ensure that it has
a letter in front of it, or a number of other tests but that
should be a decent start.
-tim
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