George Sakkis a écrit :
On Oct 14, 1:50 pm, hofer <[EMAIL PROTECTED]> wrote:
Hi,
I have multiple objects all belonging to the same class
(which I didn't implement and whose code I don't want to modify)
Now I'd like to change one method for one object only (after it has
been created) without adding any overhead
to the call of the other object's methods.
Is this possible?
Example
##### This is NOT what I'd like to do
##### as it overwrites the method for all objects of this class
o1 = aclass()
o2 = aclass()
# call original method
o1.method()
o2.method()
# overwrite the method for the entire class
aclass.method = mymethod
o1.method() # now new method
o2.method() # now new method
####### What doesn't work, but what I'd like to do
o1 = aclass()
o2 = aclass()
# call original method
o1.method()
o2.method()
# overwrite the method for the entire class
o1.method = mymethod
o1.method() # now new method
o2.method() # still old method
thanks for any pointers.
Please post the actual code that doesn't work. The following works as
expected:
>>> class A(object):
... def foo(self): return 'Original'
...
>>> a = A()
>>> b = A()
>>> a.foo()
'Original'
>>> b.foo()
'Original'
>>> b.foo = lambda: 'Modified'
>>> a.foo()
'Original'
>>> b.foo()
'Modified'
Except that b.foo is a plain function, not a method:
>>> class A(object):
... def foo(self): return "original called on %s" % self
...
>>> a = A()
>>> b = A()
>>> a.foo()
'original called on <__main__.A object at 0xb7c0c56c>'
>>> b.foo()
'original called on <__main__.A object at 0xb7c0c4ec>'
>>> b.foo = lambda: "modified called on %s" % self
>>> b.foo
<function <lambda> at 0xb7bfe9cc>
>>> b.foo()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<stdin>", line 1, in <lambda>
NameError: global name 'self' is not defined
>>> b.foo = lambda self: "modified called on %s" % self
>>> b.foo()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: <lambda>() takes exactly 1 argument (0 given)
>>>
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