On Oct 14, 3:06 am, "Gabriel Genellina" <[EMAIL PROTECTED]> wrote: > En Fri, 10 Oct 2008 14:18:53 -0300, Aaron "Castironpi" Brady > <[EMAIL PROTECTED]> escribió: > > > > > On Oct 10, 3:36 am, Bruno Desthuilliers <bruno. > > [EMAIL PROTECTED]> wrote: > >> I don't get what you're after ??? The decorator has full access to both > >> the actual params *and* the function's signature (via > >> inspect.getargspec). So your initial question "if you wanted a decorator > >> that examines the parameters to a function" seems fully answered. You > >> will indeed have to write a couple lines of code if you want the same > >> formating as the one you'd get with inspect.currentframe(), but what ? > > >> FWIW, Michele Simionato's decorator module has some trick to allow for > >> signature-preserving decorators, so you may want to have a look - but > >> I'm not sure if this would solve your problem - at least in a sane way. > > > It's not exactly the next Millennium problem, but there are some > > substantial checks you have to do on a per-parameter basis to see the > > same thing that a function sees, when all you have is *args, **kwargs. > > > You are wrapping a function with this signature: > > > def f( a, b, c= None, *d, **e ): > > > You want to find out the values of 'a', 'b', and 'c' in a decorator. > > You have these calls: > > > f( 0, 1, 'abc', 'def', h= 'ghi' ) > > f( 0, 1 ) > > f( 0, 1, h= 'abc' ) > > f( 0, 1, 'abc', c= 'def' ) #raise TypeError: multiple values > > > How do you determine 'a', 'b', and 'c'? > > I'm afraid you'll have to duplicate the logic described here: > http://docs.python.org/reference/expressions.html#id9 > To my knowledge, there is no available Python code (in the stdlib or > something) that already does that.
I wrote such a beast some time ago; it's hairy but to the best of my knowledge it seems to reproduce the standard Python logic: http://code.activestate.com/recipes/551779/ George -- http://mail.python.org/mailman/listinfo/python-list