On Oct 9, 9:01 am, Paul Rubin <http://[EMAIL PROTECTED]> wrote: > Lie Ryan <[EMAIL PROTECTED]> writes: > > in python 2.6, ast.literal_eval may be used to replace eval() for > > literals. > > What happens on literal_eval('[1]*999999999') ?
The documentation clearly states that it will fail to evaluate and raise a ValueError because there is an operation in the statement. 5*5 is NOT the literal 25, it is the equivalent to operator.mul(5, 5), and the same is true to []*x -- http://mail.python.org/mailman/listinfo/python-list