Rajanikanth Jammalamadaka:
> Is there a functional way to do this?
> I have an array [0,1,2,3,0,1,2,2,3] and I want the first chunk of
> non-decreasing values from this array (eg: In this case I want
> [0,1,2,3])
In Python sometimes the best way to write the code isn't functional,
this is readable code:
s = [3,1,2,3,0,1,2,2,3,3,2]
it = iter(s)
prec = it.next() #fix this if it can be empty
groups = [[prec]]
for x in it:
if x < prec:
groups.append([])
groups[-1].append(x)
prec = x
print groups
Output:
[[3], [1, 2, 3], [0, 1, 2, 2, 3, 3], [2]]
If you want more fancy code you may use something like this:
class Infinite:
def __cmp__(self, other):
return 0 if isinstance(other, Infinite) else 1
infinite = Infinite()
it = iter(s)
prec = infinite
groups = []
for x in it:
if x < prec:
groups.append([])
groups[-1].append(x)
prec = x
print groups
If you really want functional code you may try to use groupby().
bye,
bearophile
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