Steven Bethard wrote:
py> def defaultdict(*args, **kwargs): ... defaultfactory, args = args[0], args[1:]
which can be written more succinctly as
def defaultdict(defaultfactory, *args, **kwargs): ...
Not if you want to allow the defaultfactory to be called with a keyword argument 'defaultfactory'. Compare my code:
py> def defaultdict(*args, **kwargs):
... defaultfactory, args = args[0], args[1:]
... print defaultfactory, args, kwargs
...
py> defaultdict(dict, defaultfactory=True)
<type 'dict'> () {'defaultfactory': True}with the code you suggested:
py> def defaultdict(defaultfactory, *args, **kwargs):
... print defaultfactory, args, kwargs
...
py> defaultdict(dict, defaultfactory=True)
Traceback (most recent call last):
File "<interactive input>", line 1, in ?
TypeError: defaultdict() got multiple values for keyword argument 'defaultfactory'
Uncommon, sure, but I'd rather not rule it out if there's no need to.
STeVe -- http://mail.python.org/mailman/listinfo/python-list
