Maybe you can use __getattribute__.
I tried it, but got stuck trying to let __getattribute__
work normal without calling itself.
class A(object):
def foo(self):
print "hi"
class B(A):
def __getattribute__(self,name):
try:
fun = A.__dict__[name]
except KeyError:
fun = None
if fun and callable(fun):
self._before_any_method_of_A()
result = fun(self)
self._after_any_method_of_A()
return result
else:
# do some stuff to act normal
try:
# erm, this invokes __getattribute__, which will invoke
again,
# and again, and again...
return self.__dict__[name]
except KeyError:
pass
try:
return B.__dict__[name]
except KeyError:
pass
def _before_any_method_of_A(self):
print "before"
def _after_any_method_of_A(self):
print "after"
b = B()
b.foo()
greetings,
Almar
2008/10/3 TP <[EMAIL PROTECTED]>
> Hi everybody,
>
> I would like to be able to specialize an existing class A, so as to obtain
> a
> class B(A), with all methods of B being the methods of A preceded by a
> special method of B called _before_any_method_of_A( self ), and followed by
> a special method of B called _after_any_method_of_A( self ).
>
> The goal is to avoid to redefine explicitly in B all methods of A.
>
> Is this possible in Python?
>
> Thanks a lot
>
> Julien
>
> --
> python -c "print ''.join([chr(154 - ord(c)) for c in '*9(9&(18%.9&1+,\'Z
> (55l4('])"
>
> "When a distinguished but elderly scientist states that something is
> possible, he is almost certainly right. When he states that something is
> impossible, he is very probably wrong." (first law of AC Clarke)
> --
> http://mail.python.org/mailman/listinfo/python-list
>
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