Ivan Reborin wrote:
Hello everyone,
I was wondering if anyone here has a moment of time to help me with 2
things that have been bugging me.
1. Multi dimensional arrays - how do you load them in python
For example, if I had:
-------
1 2 3
4 5 6
7 8 9
10 11 12
13 14 15
16 17 18
-------
with "i" being the row number, "j" the column number, and "k" the ..
uhmm, well, the "group" number, how would you load this ?
If fortran90 you would just do:
do 10 k=1,2
do 20 i=1,3
read(*,*)(a(i,j,k),j=1,3)
20 continue
10 continue
How would the python equivalent go ?
2. I've read the help on the next one but I just find it difficult
understanding it.
I have;
a=2.000001
b=123456.789
c=1234.0001
How do you print them with the same number of decimals ?
(eg. 2.000, 123456.789, 1234.000)
and how do you print them with the same number of significant
decimals?
(eg. 2.000001, 123456.7, 1234.000 - always 8 decimals) ?
Is something like this possible (built-in) in python ?
Really grateful for all the help and time you can spare.
--
Ivan
I'm not sure if this is applicable to your multi-dimensional list
problem... but it sounded a bit sudoku like (with row, columns and
groups) so I thought I'd share a bit of code of developed in regards to
solving sudoku puzzles...
Given a list of 9 list elements, each with nine elements (lets call it
sudoku_grid), the following list comprehensions produce lists of indexes
into sudoku grid
vgroups = [[(x,y) for y in xrange(9)] for x in xrange(9)]
hgroups = [[(x,y) for x in xrange(9)] for y in xrange(9)]
lgroups = [[(x,y) for x in xrange(a,a+3) for y in xrange(b,b+3)]
for a in xrange(0,9,3) for b in xrange(0,9,3)]
where sudoku_grid[y][x] yields the value at position (x,y), assuming the
top left corner is indexed as (0,0)
HTH
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