You can do it with regexps too :
>------------------------------------------------------------------
import re
to_watch = re.compile(r"(?P<number>\d+)[/](?P<letter>[A-Z]+)")
final_list = to_watch.findall("12560/ABC,12567/BC,123,567,890/JK")
for number,word in final_list :
print "number:%s -- word: %s"%(number,word)
>------------------------------------------------------------------
the output is :
number:12560 -- word: ABC
number:12567 -- word: BC
number:890 -- word: JK
See you,
Kib².
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