Hi, >>> a = [1,2,3] >>> b = [3,2,1,4] >>> a = set(a) >>> b = set(b) >>> a.intersection(b) set([1, 2, 3])
Is this what you want ? cheers James On 9/8/08, mathieu <[EMAIL PROTECTED]> wrote: > Hi there, > > I am trying to write something very simple to test if a list > contains another one: > > a = [1,2,3] > > b = [3,2,1,4] > > but 'a in b' returns False. How do I check that a is indeed contained > in b ? > > thanks > > -- > http://mail.python.org/mailman/listinfo/python-list > -- -- -- "Problems are solved by method" -- http://mail.python.org/mailman/listinfo/python-list
