Hello! Executing following little program gives me an TypeError.
What makes me wonder is that foo does get an argument passed while bar doesn't. Can anyone explain why?????? Thanks Ruediger class foo(list): __hash__ = lambda x: id(x) class bar(list): __hash__ = id _s_ = set() _s_.add(foo()) _s_.add(bar()) [EMAIL PROTECTED]:~> python test01.py Traceback (most recent call last): File "test01.py", line 9, in <module> _s_.add(bar()) TypeError: id() takes exactly one argument (0 given) -- http://mail.python.org/mailman/listinfo/python-list