On Sep 3, 8:09 pm, Scott <[EMAIL PROTECTED]> wrote:
> Let's say I have an object:
>
> class foo():
> def create_another()
> return foo()
>
> def blah():
> x = self.create_another()
> ... do something with X
>
> Now I create a inherited class of this object:
>
> class bar(foo):
> ...
>
> If I call bar.create_another(), it will return a foo() instead of a
> bar(). This isn't what I want. I would like bar.create_another() to
> create an instance for bar(). Obviously I can do this by overriding
> create_another, i.e.
>
> class bar(foo):
> def create_another()
> return bar()
>
> However, is there a way for me to modify foo() so that it
> automatically creates objects of the derived class, so that I don't
> have to continue to redefine create_another() ?
>
> For example, I tried the following:
>
> def create_another()
> return self.type()()
>
> but it did not work.
>
If you want a foo object to be able to create another foo object and a
bar object to be able to create another bar object then you could do
this:
class foo():
def create_another(self):
return self.__class__()
class bar(foo):
pass
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