On 29 Aug, 19:08, Daniel <[EMAIL PROTECTED]> wrote: > > I have tried running both commands above from the mypackage directory > and unittests directory. I get the following response universtally. > > C:\mypackage>dir > Volume in drive C is Default > > Directory of C:\mypackage > > 08/29/2008 11:04 AM <DIR> . > 08/29/2008 11:04 AM <DIR> .. > 08/29/2008 11:05 AM <DIR> module1 > 08/29/2008 11:05 AM <DIR> module2 > 08/29/2008 11:06 AM <DIR> unittests > 08/29/2008 11:04 AM 0 __init__.py > 1 File(s) 0 bytes > 5 Dir(s) 55,402,070,016 bytes free
If you run unittests\alltests.py from here, sys.path will initially refer to this directory (C:\mypackage) and to anything else set up in your environment. The extra path modification that you put in alltests.py will append (or insert) the following... os.path.normpath( os.path.join( __file__, "../../" )) -> os.path.normpath( os.path.join( "C\\:mypackage\\unittests\ \alltests.py", "../../" )) -> os.path.normpath( "C\\:mypackage" ) -> "C\\:mypackage" Since the import statement then tries to access mypackage, which isn't itself in the C:\mypackage directory - it's in the C:\ directory - the import fails. The previous, automatically added entry in sys.path is duplicated by the path modifications shown above, so that won't help here, either. > C:\mypackage>dir unittests > Volume in drive C is Default > > Directory of C:\mypackage\unittests > > 08/29/2008 11:06 AM <DIR> . > 08/29/2008 11:06 AM <DIR> .. > 08/29/2008 11:05 AM 0 alltests.py > 08/29/2008 11:05 AM 0 test1.py > 08/29/2008 11:05 AM 0 test2.py > 08/29/2008 11:04 AM 0 __init__.py > 4 File(s) 0 bytes > 2 Dir(s) 55,401,988,096 bytes free Here, sys.path should refer to C:\mypackage\unittests somewhere, which won't help Python find mypackage. The path modification in alltests.py should perform as above, producing C:\mypackage which won't help. I guess the easiest thing to do is to change the path modification code to use "../../.." which should produce a reference to C:\ instead of C:\mypackage. The confusion with this particular piece of the code is the way ".." doesn't cause os.path.join to operate on the directory C:\mypackage\unittests but instead on the file C:\mypackage\unittests \alltests.py - that's almost to be expected, however, since os.path.join doesn't really know that its first argument is really a file or that ".." is being combined with a file. What I tend to do, especially with __file__, is to first use os.path.split to remove the filename - strictly speaking, it's the leafname - and then to apply the kind of modifications mentioned above, although there's probably no real difference or, indeed, any advantage with either approach. Paul -- http://mail.python.org/mailman/listinfo/python-list
