Palindrom wrote:
### Python ###
liste = [1,2,3]
def foo( my_list ):
my_list = []
The above points the my_list reference at a different object. In this
case a newly created list. It does not modify the liste object, it
points my_list to a completely different object.
### Perl ###
@lst =(1,2,3);
$liste [EMAIL PROTECTED];
foo($liste);
print "@lst\n";
sub foo {
my($my_list)[EMAIL PROTECTED];
@{$my_list}=()
}
The above code *de-references* $my_list and assigns an empty list to its
referant (@lst).
The two code examples are not equivalent.
An equivalent perl example would be as follows:
### Perl ###
@lst =(1,2,3);
$liste [EMAIL PROTECTED];
foo($liste);
print "@lst\n";
sub foo {
my($my_list)[EMAIL PROTECTED];
$my_list = [];
}
The above code does just what the python code does. It assigns a newly
created list object to the $my_list reference. Any changes to this now
have no effect on @lst because $my_list no longer points there.
n
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