On Mon, 28 Mar 2005 12:03:24 -0500, Julian Hernandez Gomez
<[EMAIL PROTECTED]> wrote:
> is there a "easy way" to make eval() convert all floating numbers to Decimal
> objects and return a Decimal?
> eval('1.00000001+0.1111111') --> convert each number to a Decimal object,
> perform the sum and obtain a Decimal object as a result?
> maybe a parser is needed, but eval() already do the job, but I need the
> precision that Decimal offers for numerical applications.
If you need the precision, why are you using strings instead of the
numbers directly?
Also, why not simply use Decimal('1.0000000') + Decimal('0.1111111') ?
--
Swaroop C H
Blog: http://www.swaroopch.info
Book: http://www.byteofpython.info
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