On Mon, 11 Aug 2008 00:27:46 -0700, Brandon wrote:
> This should be pretty simple: I have two dictionaries, foo and bar. I
> am certain that all keys in bar belong to foo as well, but I also know
> that not all keys in foo exist in bar. All the keys in both foo and bar
> are tuples (in the bigram form ('word1', 'word2)). I have to prime foo
> so that each key has a value of 1.
The old way:
foo = {}
for key in all_the_keys:
foo[key] = 1
The new way:
foo = dict.fromkeys(all_the_keys, 1)
> The values for the keys in bar are
> variable integers. All I want to do is run a loop through foo, match
> any of its keys that also exist in bar, and add those key's values in
> bar to the preexisting value of 1 for the corresponding key in foo. So
> in the end the key,value pairs in foo won't necessarily be, for example,
> 'tuple1: 1', but also 'tuple2: 31' if tuple2 had a value of 30 in bar.
Harder to say what you want to do than to just do it.
The long way:
for key in foo:
if bar.has_key(key):
foo[key] = foo[key] + bar[key]
Probably a better way:
for key, value in foo.iteritems():
foo[key] = value + bar.get(key, 0)
You should also investigate the update method of dictionaries. From an
interactive session, type:
help({}.update)
then the Enter key.
--
Steven
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