On Aug 5, 7:10 am, Marc 'BlackJack' Rintsch <[EMAIL PROTECTED]> wrote: > On Tue, 05 Aug 2008 11:39:36 +0100, Fred Mangusta wrote: > > In other words I'd like to replace all the instances of a '.' character > > with something (say nothing at all) when the '.' is representing a > > decimal separator. E.g. > > > 500.675 ----> 500675 > > > but also > > > 1.000.456.344 ----> 1000456344 > > > I don't care about the fact the the resulting number is difficult to > > read: as long as it remains a series of digits it's ok: the important > > thing is to get rid of the period, because I want to keep it only where > > it marks the end of a sentence. > > > I was trying to do like this > > > s=re.sub("[(\d+)(\.)(\d+)]","... ",s) > > > but I don't know much about regular expressions, and don't know how to > > get the two groups of numbers and join them in the sub. Moreover doing > > like this I only match things like "345.000" and not "1.000.000". > > > What's the correct approach? > > In [13]: re.sub(r'(\d)\.(\d)', r'\1\2', '1.000.456.344') > Out[13]: '1000456344' > > Ciao, > Marc 'BlackJack' Rintsch
Even faster: '1.000.456.344'.replace('.', '') => '1000456344' -- http://mail.python.org/mailman/listinfo/python-list