Hello Mike,
The reason of the problem is that the class Test was not pushed into the
sys.modules.
Use one more separate module for that stuff:
*one.py*
class Test(object):
'''just define'''
*three.py*
from one import Test
#push one.pyc to sys.modules
if __name__ == '__main__':
import two
two.run( Test() )
*two.py*
def run( a ):
from one import Test
#reuse existing Test
print type(a), Test, type(a) == Test
Regards,
Alexey
On Sat, Aug 2, 2008 at 5:16 PM, Mike Wyatt <[EMAIL PROTECTED]> wrote:
> I have a problem where type comparisons don't work in a second module when
> unit tests in the first module are run. In the example below, class Test is
> declared in one.py. When one.py is executed, it calls a method in two.py
> that imports Test from one.py. The problem is that the Test object passed
> into the run method is in the "__main__" namespace, while the Test class
> imported from one.py is in the "one" namespace. Comparing type(a) and Test
> returns False, even though they are both Test objects. How can I tweak
> these modules so that the type comparison returns True?
>
> I suppose one solution is to redesign my solution to not compare types, but
> I would still appreciate a solution for my personal knowledge.
>
> **** one.py ****
> class Test(object):
> pass
>
> if __name__ == '__main__':
> import two
> two.run( Test() )
>
> **** two.py ***
> *def run( a ):
> from one import Test
> print type(a), Test, type(a) == Test
> *
> *** Output ***
> *<class '__main__.Test'> <class 'one.Test'> False
>
>
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