On Sunday 27 March 2005 05:04 pm, Michael Spencer wrote:
> >>> def group(src):
> ... stack = []
> ... srciter = iter(src)
> ... for i in srciter:
> ... if i == "/":
> ... stack[-1].append(srciter.next())
> ... else:
> ... stack.append([i])
> ... return stack
Very pretty:
group("AGC/C/TGA/T")
[['A'], ['G'], ['C', 'C', 'T'], ['G'], ['A', 'T']]
--
James Stroud, Ph.D.
UCLA-DOE Institute for Genomics and Proteomics
Box 951570
Los Angeles, CA 90095
http://www.jamesstroud.com/
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