[EMAIL PROTECTED] wrote:
> ============================================================
> <data>
> <fonts>
> <fontData embed="true" name="Times" />
> <fontData embed="true" name="Arial" />
> </fonts>
> <color>
> </color>
> <template>
> <fonts>
> <fontData>
> <fontData embed="true"
> name="Courier">text</fontData>
> </fontData>
> <fontData embed="true" name="Helvetica" />
> </fonts>
> <width>
> </width>
> </template>
> </data>
> ============================================================
You can exploit the structure: the Elements you are looking for do not have
children, but they do have a "name" attribute.
declarations = [ fontData for fontData in root.getiterator('fontData')
if fontData.get("name") ]
This gives you a list of all "fontData" Elements that declare a font name. The
one you want is the last one, i.e. declarations[-1].
You can also do
font_names = [ fontData.get("name")
for fontData in root.getiterator('fontData')
if fontData.get("name") ]
or something like that. And if you only want the fontData Elements that appear
in the template Elements, try findall instead of getiterator:
tree.findall("//template//fontData")
("//" means: descend into the subtree, while "/" would mean: look only at the
direct children).
> f = root.getiterator('fonts')
> n = f[-1].getiterator('fontData')
You should not rely on ET returning a list from ".getiterator()", so avoid
using f[-1] here.
> fntList = []
> f = root.getiterator('fonts')
> n = f[-1].find('fontData')
> for i in n:
> fntList.append(i.get('name'))
>
> print fntList
> ============================================================
>
> This code just gave me ['Courier']. Now if I change 'find' to 'findall' then
> I'll get [None, 'Helvetica']. Not exactly sure what exactly that's doing.
The first value (None) comes from the "fontData" Element that does not have a
"name" attibute. The path expression "fontData" means: find all children that
are named "fontData". As above, what you want is ".//fontData".
Stefan
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