On Tue, Jul 29, 2008 at 12:17 AM, Piyush Anonymous
<[EMAIL PROTECTED]> wrote:
> class MyObject:
> def __init__(self, name):
> self.name = name
>
> def do_this_default(self):
> print "default do_this implementation for %s" % self.name
>
> def custom_do_this(): #method to be added
> print "custom do_this implementation for %s" % self.name
>
>
> def funcToMethod(func,clas,method_name=None):
> """Adds func to class so it is an accessible method; use method_name to
> specify the name to be used for calling the method.
> The new method is accessible to any instance immediately."""
> import new
> method = new.instancemethod(func,None,clas)
> print method
> if not method_name: method_name=func.__name__
> clas.__dict__[method_name]=func
>
>
> myobj = MyObject('myobj1')
> funcToMethod(custom_do_this,MyObject) #trying 2 add method to class not
> instance
> print myobj.custom_do_this()
>
> ---
> Error I am getting;
> TypeError: custom_do_this() takes no arguments (1 given)
>
> Why am I getting it?
>
If your method is going to be bound to an instance, then it needs the
expected signature: the first parameter is always a reference to the
instance ("self"). Change it to "custom_do_this(self)" and it should
work.
> Also how can I do this in new style class (inherited from 'object')?
>
>
What did you try and how did it fail? This seems to work:
def foo(self):
print 'foo'
class Bar(object):
pass
Bar.foobar = new.instancemethod(foo, None, Bar)
b = Bar()
b.foobar()
>
>
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