josh logan wrote:
Hello,
I need a round function that _always_ rounds to the higher integer if
the argument is equidistant between two integers. In Python 3.0, this
is not the advertised behavior of the built-in function round() as
seen below:
round(0.5)
0
round(1.5)
2
round(2.5)
2
I would think this is a common need, but I cannot find a function in
the Python library to do it. I wrote my own, but did I miss such a
method in my search of the Python library?
Thanks
I think what you want is something like:
math.ceil(x-0.4999999999999)
-Larry
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