Lanny wrote:
I've used glob.glob to get a list of files in a directory
and now I want to use os.system to execute one of
those files, the problem is that python automatically
puts a escape charater infront of the back slashes
so the os.system gets X:\\####\\####\\ and is useless,
No, it doesn't. The backslash doubling only happens when you "echo" a
variable to the terminal in interactive mode. If you want to know that
the string really contains, use "print".
Here's an example:
>>> import glob
>>> files = glob.glob("\\bin\\ls.exe")
>>> files
['\\bin\\ls.exe']
>>> files[0]
'\\bin\\ls.exe'
>>> print files[0]
\bin\ls.exe
>>> import os
>>> os.system(files[0])
Demo Makefile.pre.in Parser
Doc Misc Python
Grammar Modules README
Include Objects RISCOS
LICENSE PC Tools
Lib PCbuild configure
Mac PCbuild8 configure.in
Btw, if you want to pass arguments to the program, you might want to use
the "subprocess" module instead, since it handles escaping and quoting
for you all by itself:
>>> import subprocess
>>> subprocess.call([files[0], "-l"])
total 479
drwxr-xr-x 26 1006 everyone 0 Oct 14 2006 Demo
drwxr-xr-x 33 1006 everyone 0 Oct 14 2006 Doc
drwxr-xr-x 6 1006 everyone 0 Oct 14 2006 Grammar
...
There's also a function called "os.startfile", which can be used to
"open" an arbitrary file (in the same as if you'd double-click on it in
the explorer).
> I think I need to convert my string to a raw string but
> I don't know how.
Raw strings are an alternate syntax for adding string literals to your
source code, and has nothing to do with output.
</F>
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