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Diez B. Roggisch wrote:
> Dave Challis wrote:
>
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>>
>> I'm trying to write some code which:
>> 1. Finds all modules in a plugin directory
>> 2. Imports those modules
>> 3. Creates an instance of each object defined in the module (each module
>> will contain exactly 1 object, which is a subclass of 'Plugin')
>>
>> The closest I've come so far is with something like:
>>
>> In plugin.py:
>> # taken from http://docs.python.org/lib/built-in-funcs.html
>> def my_import(name):
>> mod = __import__(name)
>> components = name.split('.')
>> for comp in components[1:]:
>> mod = getattr(mod, comp)
>> return mod
>>
>> def import_plugins():
>> mods = []
>> for filename in os.listdir('/plugins'):
>> if filename.endswith('.py'):
>> name = os.path.splitext(filename)[0]
>> mods.append(my_import('plugins.' + name))
>> return mods
>>
>> class Plugin(object):
>> pass
>>
>>
>> In plugins/exampleplugin.py:
>> class ExamplePlugin(Plugin):
>> def __init__(self):
>> pass
>>
>>
>> Calling import_plugins() then gives me a list containing references to
>> modules.
>>
>> How can I loop through that list and create an instance of whatever
>> object was defined within the module? (In this case I'd want to
>> construct an instance of ExamplePlugin)
>
>
> Like this:
>
> for name in dir(plugin):
> thing = getattr(plugin, name)
> try:
> if issubclass(thing, Plugin):
> thing()
> except ValueError: # issubclass sucks
> pass
>
> Diez
Thanks for that, it helped as a starting point. I had some trouble with
using issubclass though (issubclass(Plugin, Plugin) returns true), which
was complicating things.
I modified your code to the following instead (which may well have it's
own pitfalls I'm not aware of!):
for name in dir(plugin):
thing = getattr(plugin, name)
if hasattr(thing, '__bases__') and \
getattr(thing, '__bases__')[0] == Plugin:
thing()
Cheers,
Dave
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><> o ) <><
. ( (
) Dave Challis <>< ) ) ><>
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