Just to throw my hat in the ring, this is another way you can do this: [(lambda x : [int(ii) for ii in x])(y) for y in a]
However, I do think dusans way is more elegant. Best, R On Tue, Jul 22, 2008 at 4:58 PM, dusans <[EMAIL PROTECTED]> wrote: > >>> a = [['1', '2'], ['3'], ['4', '5', '6'], ['7', '8', '9', '0']] > >>> [map(int, i) for i in a] > [[1, 2], [3], [4, 5, 6], [7, 8, 9, 0]] > > On Jul 21, 9:06 pm, Samir <[EMAIL PROTECTED]> wrote: > > Hi Everyone, > > > > I am relatively new to Python so please forgive me for what seems like > > a basic question. > > > > Assume that I have a list, a, composed of nested lists with string > > representations of integers, such that > > > > a = [['1', '2'], ['3'], ['4', '5', '6'], ['7', '8', '9', '0']] > > > > I would like to convert this to a similar list, b, where the values > > are represented by integers, such as > > > > b = [[1, 2], [3], [4, 5, 6], [7, 8, 9, 0]] > > > > I have unsuccessfully tried the following code: > > > > n = [] > > for k in a: > > n.append([int(v) for v in k]) > > print n > > > > Does anyone know what I am doing wrong? > > > > Thanks in advance. > > > > Samir > > -- > http://mail.python.org/mailman/listinfo/python-list >
-- http://mail.python.org/mailman/listinfo/python-list
