On Jul 18, 11:15 pm, Terry Reedy <[EMAIL PROTECTED]> wrote: > No, round() return binary floats that, in general, cannot represent > decimal floats exactly. Formatted printing gives what you expect. > >>> '%8.2f' % x > ' 3499.35'
Sure. But it's still true that the second printed value (printed as 3499.3499999999999) is strictly less than 3499.35, so when rounding to 1 decimal place an ideal rounding routine would round it *down* to 3499.3 instead of up to 3499.4. This is what '%.1f' does, for example, on a platform where printf does correct rounding: Python 2.5.1 (r251:54863, Jan 17 2008, 19:35:17) [GCC 4.0.1 (Apple Inc. build 5465)] on darwin Type "help", "copyright", "credits" or "license" for more information. >>> x = 3499.35 >>> x 3499.3499999999999 >>> print '%.1f' % x 3499.3 >>> print round(x, 1) 3499.4 Mark -- http://mail.python.org/mailman/listinfo/python-list
