-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 I think you're over-complicating this. I'm assuming that you're going to do a line graph of some sorta, and each new line of the file contains a new set of data.
The problem you mentioned with your regex returning a match object rather than a string is because you're simply using a re function that doesn't return strings. re.findall() is what you want. That being said, here is working code to mine data from your file. [code] line = 'c afrac=.7 mmom=0 sev=-9.56646 erep=0 etot=-11.020107 mad=-3.597647 3pv=0' energypat = r'\betot=(-?\d*?[.]\d*)' #Note: To change the data grabbed from the line, you can change the #'etot' to 'afrac' or 'emad' or anything that doesn't contain a regex #special character. energypat = re.compile(energypat) re.findall(energypat, line)# returns a STRING containing '-12.020107' [/code] This returns a string, which is easy enough to convert to an int. After that, you can datapoints.append() to your heart's content. Good luck with your work. [EMAIL PROTECTED] wrote: > Hello, > > I am new to Python, with a background in scientific computing. I'm > trying to write a script that will take a file with lines like > > c afrac=.7 mmom=0 sev=-9.56646 erep=0 etot=-11.020107 emad=-3.597647 > 3pv=0 > > extract the values of afrac and etot and plot them. I'm really > struggling with getting the values of efrac and etot. So far I have > come up with (small snippet of script just to get the energy, etot): > > def get_data_points(filename): > file = open(filename,'r') > data_points = [] > while 1: > line = file.readline() > if not line: break > energy = get_total_energy(line) > data_points.append(energy) > return data_points > > def get_total_energy(line): > rawstr = r"""(?P<key>.*?)=(?P<value>.*?)\s""" > p = re.compile(rawstr) > return p.match(line,5) > > What is being stored in energy is '<_sre.SRE_Match object at > 0x2a955e4ed0>', not '-11.020107'. Why? I've been struggling with > regular expressions for two days now, with no luck. Could someone > please put me out of my misery and give me a clue as to what's going > on? Apologies if it's blindingly obvious or if this question has been > asked and answered before. > > Thanks, > > Nicole -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.4.9 (MingW32) Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org iEYEARECAAYFAkiAqiAACgkQLMI5fndAv9h7HgCfU6a7v1nE5iLYcUPbXhC6sfU7 mpkAn1Q/DyOI4Zo7QJhF9zqfqCq6boXv =L2VZ -----END PGP SIGNATURE----- -- http://mail.python.org/mailman/listinfo/python-list
