On 15 juil, 01:24, [EMAIL PROTECTED] wrote:
> Greetings.
>
> I am looking for a way to achieve method behavior for a class I
> created. That is, it has a __call__ method, so can be called like a
> function. But I also want it to be treated as a method when it appears
> in a class body.
You need to implement the descriptor protocol the same way the
function type do.
import types
class Foo(object):
def __call__(self, instance):
print "%s - %s" % (self, instance)
def __get__(self, instance, cls):
return types.MethodType(self, instance, cls)
class Bar(object):
foo = Foo()
b = Bar()
b.foo()
> I know this has to do with writing the __get__
> method of foo, but I am wondering if there is perhaps some class I can
> just inherit from to get the proper __get__, which behaves identically
> to that of regular Python functions.
Extending types.FunctionType doesn't work OOTB (there's some
incompatibility wrt/ metaclasses)
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