On 25 Mar 2005 07:34:38 -0800, Keith <[EMAIL PROTECTED]> wrote:
> Is there a function for comparing version numbers?
>
> E.g.
>
> 0.1.0 < 0.1.2
> 1.876b < 1.876c
> 3.2.2 < 3.4
>
Not by default AFAIK. How about something like (untested):
def test_version(v1, v2):
v1, v2 = v1.split('.'), v2.split('.')
for x, y in zip(v1, v2):
if x < y: return v1
if y > x: return v2
It assumes that v1 and v2 have the same amount of '.'s and that all of
the version numbers are of the same length (i.e. 1.1000 would be <
1.999). How general do you need to be?
Peace
Bill Mill
bill.mill at gmail.com
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