En Fri, 11 Jul 2008 03:51:39 -0300, Uwe Schmitt
<[EMAIL PROTECTED]> escribi�:
On 1 Jul., 15:15, Mel <[EMAIL PROTECTED]> wrote:
rocksportrockerwrote:
> the following code does not work until I ommit the "a=0" statement.
> def test():
> exec "a=3" in locals()
> print a
> a=0
> test()
> print raises:
> UnboundLocalError: local variable 'a' referenced before
> assignment
> Can anybody explain what is going wrong here ?
AFAIK, local variables are implemented rather like __slots__ in
new-style
classes. This is a very valuable efficiency measure, but it can cause
this
kind of trouble. Without `a=0`, the bytecode compiler makes no slot
for a,
Thanks for your answer. I wonder if this is a bug, or did I miss
something
in the docs ???
Read the warnings in the docs for the locals() builtin function:
http://docs.python.org/lib/built-in-funcs.html#l2h-47
and the execfile function:
http://docs.python.org/lib/built-in-funcs.html#l2h-26
--
Gabriel Genellina
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