Wow - Alex Martelli's 'Black Magic' Pycon notes
http://www.python.org/pycon/2005/papers/36/pyc05_bla_dp.pdf

include this gem:
> Functions 'r descriptors
> def adder(x, y): return x + y
>     add23 = adder.__get__(23)
>     add42 = adder.__get__(42)
> print add23(100), add42(1000)
> 123 1042

This means that you can do (left) currying without a separate curry function
(Of course, google reveals that the idea has been discussed before,
http://mail.python.org/pipermail/python-dev/2003-October/038933.html)


Although it's less flexible than a general curry function, 'method currying' is much faster, e.g., compare two functions for tail-filtering an iterator:


def filtertail(op, iterable):
    """Recursively filter the tail of an iterator, based on its head
        Useful for succinct (though not very fast) implementations
        of sieve of eratosthenes among other"""
    iterator = iter(iterable)
    while 1:
        head = iterator.next()
        yield head
        iterator = it.ifilter(curry(op,Missing,head), iterator)

def filtertail2(op, iterable):
    """An alternative to filtertail, using Alex Martelli's observation
        that functions are descriptors.  Will not work for built-in
        functions that lack a __get__ method"""
    iterator = iter(iterable)
    opcurry = op.__get__
    while 1:
        head = iterator.next()
        yield head
        iterator = it.ifilter(opcurry(head), iterator)

using these generator functions, a Sieve of Eratosthenes can be written as:

primes = list(filtertail(operator.mod, xrange(2,N)))
or
primes = list(filtertail2(lambda head, tail: tail % head, xrange(2,N)))

but the second version, using 'method currying' is 4 times the speed, despite not using the stdlib operator.mod function

def timethem(N):
    import time
    t1 = time.clock()
    p = list(filtertail(op.mod, xrange(2,N)))
    t2 = time.clock()
    p = list(filtertail2(lambda head, tail: tail % head, xrange(2,N)))
    t3 = time.clock()
    return t2-t1, t3-t2

 >>> timethem(10000)
 (3.8331997502475588, 0.79605759949936328)
 >>> timethem(100000)
 (240.68151008019186, 61.818026872130304)
 >>>

of course, neither version is anywhere near the most efficient Python implementation - this is a comparison of currying, not sieving.


BTW, here's the curry function I used (it could probably be faster; I'm not sure what/where the future stdlib version is)



Missing = Ellipsis def curry(*cargs, **ckwargs): fn, cargs = cargs[0], cargs[1:] if cargs[0] is Missing: while cargs[0] is Missing: # rightcurry cargs = cargs[1:] def call_fn(*fargs, **fkwargs): d = ckwargs.copy() d.update(fkwargs) return fn(*(fargs+cargs),**d) name = "%s(...,%s)" % (fn.__name__, ",".join(repr(i) for i in cargs)) else: def call_fn(*fargs, **fkwargs): d = ckwargs.copy() d.update(fkwargs) return fn(*(cargs + fargs), **d) name = "%s(%s,...)" % (fn.__name__, ",".join(repr(i) for i in cargs)) call_fn.func_name = name call_fn.curry = True return call_fn

Michael

--
http://mail.python.org/mailman/listinfo/python-list

Reply via email to