On Jun 23, 9:23 am, Paul Hankin <[EMAIL PROTECTED]> wrote: > On Jun 23, 10:32 am, cirfu <[EMAIL PROTECTED]> wrote: > > > [a+b for a,b in zip(xrange(1,51), xrange(50,0,-1))] > > > [51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, > > 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, > > 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51, 51] > > > i want to add all the elemtns a s well. can i do this all in a > > listcomprehension? > > > i can do this ofc: > > reduce(lambda x,y:x+y,[a+b for a,b in zip(xrange(1,51), > > xrange(50,0,-1))]) > > > but reduce is a functional way of doing it, what is the more pythonic > > way of doing this? > > Use the builtin 'sum' function. > > sum(a + b for a, b in zip(xrange(1, 51), xrange(50, 0, -1))) >
Instead of sum(a + b for a, b in zip(foo, bar)) why not use sum(foo) + sum(bar) ? -- http://mail.python.org/mailman/listinfo/python-list
