On Jun 21, 8:52 am, Peter Otten <[EMAIL PROTECTED]> wrote: > eliben wrote: > > On Jun 20, 2:44 pm, Peter Otten <[EMAIL PROTECTED]> wrote: > >> eliben wrote: > >> > Additionally, I've found indentation to be a problem in such > >> > constructs. Is there a workable way to indent the code at the level of > >> > build_func, and not on column 0 ? > > >> exec"if 1:" + code.rstrip() > > >> Peter > > > Why is the 'if' needed here ? I had .strip work for me: > > A simple .strip() doesn't work if the code comprises multiple lines: > > >>> def f(): > > ... return """ > ... x = 42 > ... if x > 0: > ... print x > ... """ > ...>>> exec "if 1:\n" + f().rstrip() > 42 > >>> exec f().strip() > > Traceback (most recent call last): > File "<stdin>", line 1, in <module> > File "<string>", line 2 > if x > 0: > ^ > IndentationError: unexpected indent >
I see. In my case I only evaluate function definitions with 'exec', so I only need to de-indent the first line, and the others can be indented because they're in a new scope anyway. What you suggest works for arbitrary code and not only function definitions. It's a nice trick with the "if 1:" :-) -- http://mail.python.org/mailman/listinfo/python-list
