Gabriel Genellina <[EMAIL PROTECTED]> wrote: > [(not x%3 and not x%5 and "FizzBuzz") or (not x%3 and "Fizz") or (not x%5 > and "Buzz") or x for x in xrange(1,101)]
Rather unpleasant. Note that a number is zero mod both 3 and 5 if and only if it's zero mod 15. But we can do better. A simple application of Fermat's Little Theorem (to distinguish units mod 3 and 5 from non-units) gives us this: [['FizzBuzz', 'Buzz', 'Fizz', False][pow(i, 2, 3) + 2*pow(i, 4, 5)] or str(i) for i in xrange(1, 101)] This is still inelegant, though. We can glue the results mod 3 and 5 together using the Chinese Remainder Theorem and working mod 15 instead. For example, [['Fizz', 'FizzBuzz', False, None, 'Buzz'][(pow(i, 4, 15) + 1)%7] or str(i) for i in xrange(1, 101)] (A less mathematical approach would just use i%15 to index a table. But that's not interesting. ;-) ) -- [mdw] -- http://mail.python.org/mailman/listinfo/python-list
