On Wed, 11 Jun 2008 01:05:45 +0000, asdf wrote: >> Well, there's a few ways you could approach it. >> >> You could create a cgi program from your script - this is probably the >> solution you're looking for. >> >> > Output from the script does come up very often. There is a new output > every 10 secs and it's possible that the script might be run > indefinitely. Basically I want all that output displayed in a web > browser
Here's a simplified Django and AJAX solution: 1. Install Django http://www.djangoproject.com/documentation/install/ and choose the place to strore your Django apps 2. Run 'python django-admin.py startproject YOURPROJECTNAME' 3. Create views.py file inside YOURPROJECTNAME directory with something like this: from datetime import datetime from django.http import HttpResponse # import your script here def myscript(request): output = """\ <html> <body> <script type="text/javascript"> function ajaxFunction() { var xmlHttp; try { // Firefox, Opera 8.0+, Safari xmlHttp=new XMLHttpRequest(); } catch (e) { // Internet Explorer try { xmlHttp=new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { try { xmlHttp=new ActiveXObject("Microsoft.XMLHTTP"); } catch (e) { alert("Your browser does not support AJAX!"); return false; } } } xmlHttp.onreadystatechange=function() { if(xmlHttp.readyState==4) { document.getElementById("hello").innerHTML=xmlHttp.responseText; setTimeout('ajaxFunction();', 1000); } } xmlHttp.open("GET", "../ajax/", true); xmlHttp.send(null); } window.onload = ajaxFunction; </script> <div id="hello"></div> </body> </html>""" return HttpResponse(output) def ajax(request): output = """ <p>Hello World from Django and AJAX</p> <p>Current time is: %s</p> """ % str(datetime.now())[11:19] return HttpResponse(output, mimetype="text/plain") Note, that refresh time is in 'setTimeout('ajaxFunction();', 1000);' in this example it is 1 second. 3. edit urls.py inside YOURPROJECTNAME directory to something like this: from django.conf.urls.defaults import * urlpatterns = patterns('', (r'^myscript/$', 'YOURPROJECTNAME.views.myscript'), (r'^ajax/$', 'YOURPROJECTNAME.views.ajax'), ) 4. run 'python manage.py runserver' inside YOURPROJECTNAME directory 5. point your browser to 'http://127.0.0.1:8000/myscript/' and you'll see the result. 6. Deploy your app to Apache web server http://www.djangoproject.com/documentation/modpython/ http://www.djangoproject.com/documentation/fastcgi/ Hope this Django/AJAX introduction is helpfull Please note that this code is extremely simplified you probably need to learn more about Django and AJAX/Javascript by yourself Ivan -- http://mail.python.org/mailman/listinfo/python-list
