On Jun 8, 2:58 am, Hans Nowak <[EMAIL PROTECTED]> wrote: > Kalibr wrote: > > On Jun 7, 1:20 pm, Hans Nowak <[EMAIL PROTECTED]> wrote: > >> Kalibr wrote: > >>> I've been developing a small script to fiddle with classes, and came > >>> accross the following problem. Assuming I get some user input asking > >>> for a number, how would I spawn 'n' objects from a class? > >>> i.e. I have a class class 'user' and I don't know how many of them I > >>> want to spawn. > >>> Any ideas? > >> Sure. This will give you a list of n instances of user: > > >> [user() for i in range(n)] > > >> Of course, you could also use a good old for loop: > > >> for i in range(n): > >> u = user() > >> ...do something with u... > > >> Hope this helps! > > >> -- > >> Hans Nowak (zephyrfalcon at gmail dot com)http://4.flowsnake.org/ > > > whoops, replied to author.... > > > What I wanted to ask before was won't 'u' be overwritten with a new > > object each time the loop ticks over? > > Yes, so you have to store it somewhere, if you want to keep the object around. > The list comprehension mentioned above stores all the objects in a list, after > which they can be accessed at will via indexing. > > > what I want to do is have, say 5 users in a game, so I'd have to spawn > > 5 objects. I can't do that because I have'nt hardcoded any object > > names for them. > > > or does it somehow work? how would I address them if they all have the > > name 'u'? > > users = [user() for i in range(n)] > > # use: users[0], users[1], etc > > -- > Hans Nowak (zephyrfalcon at gmail dot com)http://4.flowsnake.org/
Ok, wait, I see where this is going. I just did the list comprehension. I was under some misguided idea that you actually had to have a unique variable name for all the new objects you spawned. Thanks for all you help guys! -- http://mail.python.org/mailman/listinfo/python-list
