On 3. Jún, 23:08 h., Christian Heimes <[EMAIL PROTECTED]> wrote: > [EMAIL PROTECTED] schrieb: > > > Hello, > > > I am testing object identity. > > > If I do it from the interpreter, I get strange results. > > >>>> print [] is [] > > False > > >>>> print id([]), id([]) > > 3083942700 3083942700 > > > Why is that? Isn't this an error? > > No, it's not an error. You are getting this result because the list > implementation keeps a bunch of unused list objects in a free list. It's > an optimization trick. Python has to create two different list objects > for "[] is []" while it can reuse the same list object for id([]) == id([]). > > Christian
Aha. Thanks. jan bodnar -- http://mail.python.org/mailman/listinfo/python-list
