On May 28, 12:01 pm, RossGK <[EMAIL PROTECTED]> wrote:
> I'm a newbie to python threads, and playing with some simple client
> server stuff and lots of print statements.
>
> My server thread launched with
> self.worker = WorkerThread(self)
> completes an interaction and then if I check on it's status with
> print "Status:", self.worker I get Status none
>
> A client thread behaves differently. Launched as
> self.clientWorker( = ClientThreadself)
> when it finishes it's work, I instead get:
> Status: <ClientThread(Thread-2, stopped)>
>
> If I check the isAlive status on each of those, self.worker.isAlive
> throws an exception, 'cause there is nothing there anymore to check
> isAlive on. But self.clientWorker comes back as False, since it is a
> stopped thread and hasn't gone away (which I'd like it to after it
> finishes its work).
>
> So my question is when a thread finishes its work how do I more
> predictably control whether it is just stopped, or goes away all
> together? I don't want to do a double nested 'if' statement to check
> if it exists before I check if it's alive.
Pls ignore the obvious typos, this isn't a syntax question and google
groups seems to be messing with my typing and spacing(!) e.g.
> self.clientWorker( = ClientThreadself)
should have read
self.clientWorker = ClientThread(self)
As I swear I had typed it...
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